The relation between phase difference $(\Delta \phi)$ and path difference $(\Delta x)$ is:
- A$\Delta \phi = \frac{2\pi}{\lambda} \Delta x$
- B$\Delta \phi = 2\pi \lambda \Delta x$
- C$\Delta \phi = \frac{2\pi \lambda}{\Delta x}$
- D$\Delta \phi = \frac{2 \Delta x}{\lambda}$
Explore More
Similar Questions
The equations of two simple harmonic waves are given by $Y_1 = 2 \sin 8 \pi \left(\frac{t}{0.2} - \frac{x}{2}\right) \text{ m}$ and $Y_2 = 4 \sin 8 \pi \left(\frac{t}{0.16} - \frac{x}{1.6}\right) \text{ m}$. Then both waves have:
DifficultMHT CET 2021
View SolutionWrite the equation of displacement of an element of a medium in a harmonic wave.
Medium
View SolutionIf the wave equation is $y = 0.08 \sin \frac{2\pi}{\lambda} (200t - x)$,then the velocity of the wave will be:
Easy
View SolutionWrite the definition of the angular frequency of a wave and its $SI$ unit.
Medium
View Solution$A$ wave on a string is travelling and the displacement of particles on it is given by $x = A \sin (2t - 0.1x)$. Then the wavelength of the wave is
MediumAIIMS 2009
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo